hi
here I tried autorouting but some connections are still unconnected. how can i connect them ?
Now you have learned that layouting is hard to do for the computer. (and for humans as well.)
I fear connecting everything will be a lot of work. (For someone experienced 2 or 3 days. more than one week for someone who has no experience.)
First you will need to play around with the placement of the parts. (Yes this means maybe deleting some or all of the work you have already done.)
Make sure that you have as little crossing ratsnets as possible before you lay down your first track.
When you start laying down traces start with the most important tracks. (High frequency tracks, analog tracks.) This should be kept as short as possible and they should also not switch layers too often.
Also if you use a micro processor and have some freedom in which pin should do what, you can change around some pins to reduce the number of ratsnet crossings further.
The same holds for connectors. If you have freedom over what pin is used for what you can change pins around to make your live easier.
Sometimes it is also usefull to put chips with a high pincount at an angle of 45 degrees. This can make the fanout easier. (But make sure your manufacturer can handle this.)
If you hit another roadblock rethink your component placement again. (It will take you a few iterations until you are happy.)
Also if you can, use more layers. (4 layers could be a good start. The outer 2 layers for signals the inner layers for ground and positive supply)
Also next time you post a screenshot show us the layer tab so that we now what color is what layer.
In short there is now fast solution to your problem.
3 Likes
Read this thread from top to bottom and contact @arvimg, you two might be able to exchange some thoughts and concepts as he went through this recently…
2 Likes
Hi,
I tried a little, I managed to get all connections is there anything else should I need to look for ?
And for the both of the layers top and Bottom I put them both on ground potential with the filled zones. would that be ok or should i change it to something else ?
Hello
Is it possible if I can use the same schematic and footprints to make another layout. If yes how can i do it without affecting the older PCB layout? waiting for reply 
Thanks
Just copy your project directory.
(this is the directory that holds your .pro, .pcb_new, .sch,… files)
I do this all the time. My project folders are then normally named something like “project_name_Vx.y”.
This thread from today might also be informative to you:
1 Like
Thanks
but it doesn’t open up the schematic but just the layout. Is it that how it is?
Do not dry clean … 
1 Like
It is either the grid origin or the auxilary axis.
You can “delete” them by setting them to 0,0
(Left top corner of the sheet.)
These two buttons set the origins. (click the image to see the full screenshot.)
1 Like
I never auto route small boards. Humans (+ perhaps monkeys==shakespeare) can do a better job.
On 2 layer boards, I try to keep the bottom layer for ground connections.
And am careful to keep IC supply bypass capacitors close to their owners.
Then I try to route, minimising vias. (Every through hole is a possible point of failure).
Lastly, i try to shorten & thicken voltage supply tracks.
Im sure other contributors have a similar process.
2 Likes
yeah i had to start it over hoping to do it better this time 
Hi,
I was trying to calculte the track width with PCB calcultor but i don’t think it is correct. what could be wrong with it ?
Are you sure your copper layer thickness is 0.035 mil?
This would be 0.889 µm
Could it be that you meant 0.035 mm = 35 µm?
2 Likes
Your trace thickness of .035 mil is the problem. Standard 1oz Copper board is ~ 1.37mil. So this is more like a thin plating thickness.
Of course, you could avoid all this nonsense and just use sensible metric units …
2 Likes
1 mil (imperial) = 0.0254 mm = 25.4 µm = 1.26262e-7 furlongs 
2 Likes
0.035 is the default for mm. Changing the units does not cause the values to be converted, something that should be fixed in my opinion.
The 10 mil length should have been the first clue. 
And 1.80387e+12 furlongs/fornight = ??
(Besides enough characters to make a post.)
Dale
The width is what gets calculated. It is not an input
(The reason he asked is because this value did not make sense to him.)
1 Like
yes, thanks.
finally someone understood what I was trying to ask but the answers were quite helpful.
again thanks everyone